In a g.p. a 81 r −1/3 then find a3
WebMar 19, 2024 · Ask a question for free Get a free answer to a quick problem. Most questions answered within 4 hours. Weba3-8b3 Final result : (a - 2b) • (a2 + 2ab + 4b2) Step by step solution : Step 1 :Equation at the end of step 1 : (a3) - 23b3 Step 2 :Trying to factor as a Difference of Cubes: 2.1 ... a3 −b3 = …
In a g.p. a 81 r −1/3 then find a3
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Web(1) Find as if a4 = 81, and r=-3 (2) Find as if a2 = 9 and a3 = 3 (3) Find the sum of the first five terms if a1 = 3 and r = -2 (4) Find the sum of the first five terms of the sequence 6, 12, … WebApr 27, 2024 · These variable names, a1, r, are commonly used in relationship to geometric sequences. We assume you want the terms of a geometric sequence with these characteristics. a1 is the first term. r is the ratio between terms, so is the factor to find the next term from the previous one. a1 = 3 (given) a2 = a1×r = 3×(-2) = -6 a3 = a2×r = (-6)(-2) …
WebJan 31, 2014 · question_answer Answers (2) person Kishore Kumar Given (a+1/a) 2 = 3 Therefore (a + 1/a) = √3 Recall the formula, (a 3 + b 3) = (a + b) 3 - 3ab (a + b) Therefore, (a3 + 1/a3) = (a + 1/a)3 - 3 x a x 1/a (a + 1/a) = (√3)3 - 3 (√3) = 3√3 - 3 (√3 = 0 Recommend (6) Comment (0) person Parthasaradhi M Member since Apr 1, 2024 Recommend (1) … WebFind the sum of the first 6 terms of a GP whose first term is 2 and the common difference is 4. Solution: Given, First term = a = 2, Common ratio = r = 4 and n = 6 As we know, the sum …
WebFind a3 + 1/a3 if a + 1/a = 5. Login. Study Materials. NCERT Solutions. NCERT Solutions For Class 12. NCERT Solutions For Class 12 Physics; NCERT Solutions For Class 12 Chemistry; NCERT Solutions For Class 12 Biology; NCERT Solutions For … WebMay 7, 2024 · If a1,a2,a3 are in gp such that a1 + a2 + a3 =13 and (a1)^2 +(a2)^2 +(a3)^2 = 91 then find a and r - 17216831
WebWrite three terms of the GP when the first term a and the common ratio r are given A) a=4:r=3 B)a= 5;r= 51 C)a=81;r= 3−1 D)a= 641;r=2 Medium Solution Verified by Toppr As …
WebSolution Verified by Toppr It is given that, a−b=7 let us cube on both sides, we get (a−b) 3=(7) 3 a 3+b 3−3ab(a−b)=343 133−3ab×7=343 133−21ab=343 −21ab=343−133 … portland oregon asian antique shopsWebA geometric progression (GP) can be written as a, ar, ar 2, ar 3, … ar n – 1 in the case of a finite GP and a, ar, ar 2,…,ar n – 1 … in case of an infinite GP. We can calculate the sum to n terms of GP for finite and infinite GP using some formulas. Also, it is possible to derive the formula to find the sum of finite and finite GP separately. optimal workshop testerWebthe order of g is pk, and the order of gpk−1 is p. 3. Let p and q be prime and q ≡ 1 mod p. If G = pnq, then G is solvable. Solution. By the second Sylow theorem there is only one Sylow p-subgroup. Denote it by P. Then P is normal since gPg−1 = P for any g ∈ G. As we proved in class P is solvable, the quotient G/P is solvable. portland oregon art museum gift shopWebNov 27, 2024 · The 3rd and 8th term of a GP are 1/3 and 81, respectively. Find the 2nd term. (a) 3 (b) 1 (c) 1/27 (d) 1/9. LIVE Course for free. Rated by 1 million+ students Get app now … optimal workshop first click testingportland oregon art gallery trumpWebNov 6, 2024 · First term, a = 81 2nd term = ar = 81* 1/3 = 27. 3rd term term = 81* (1/3) ²= 9 4th term = 81 * (1/3)³ = 3 So the GP is 81, 27, 9 , 3, 1 .... Advertisement Advertisement New … portland oregon area golf coursesWebThat is a subset of your group (and even more so a subgroup, albeit unrelated here). And if the group generated is the size of your desired group (you should know the size of A 3 ), … optimale features hinzufügen